346(x)=0.00012x^2+200

Solution for 346(x)=0.00012x^2+200 equation:

346(x)=0.00012x^2+200

We move all terms to the left:

346(x)-(0.00012x^2+200)=0

We get rid of parentheses

-0.00012x^2+346x-200=0

a = -0.00012; b = 346; c = -200;
Δ = b2-4ac
Δ = 3462-4·(-0.00012)·(-200)
Δ = 119715.904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(346)-\sqrt{119715.904}}{2*-0.00012}=\frac{-346-\sqrt{119715.904}}{-0.00024}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(346)+\sqrt{119715.904}}{2*-0.00012}=\frac{-346+\sqrt{119715.904}}{-0.00024}
$